Integrand size = 27, antiderivative size = 193 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=\frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {15}{16} d^7 e \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )-3 d^7 e \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \]
[Out]
Time = 0.20 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {1821, 1823, 829, 858, 223, 209, 272, 65, 214} \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=-\frac {15}{16} d^7 e \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )-3 d^7 e \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}+\frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2} \]
[In]
[Out]
Rule 65
Rule 209
Rule 214
Rule 223
Rule 272
Rule 829
Rule 858
Rule 1821
Rule 1823
Rubi steps \begin{align*} \text {integral}& = -\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {\int \frac {\left (d^2-e^2 x^2\right )^{5/2} \left (-3 d^4 e+3 d^3 e^2 x-d^2 e^3 x^2\right )}{x} \, dx}{d^2} \\ & = -\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}+\frac {\int \frac {\left (21 d^4 e^3-21 d^3 e^4 x\right ) \left (d^2-e^2 x^2\right )^{5/2}}{x} \, dx}{7 d^2 e^2} \\ & = \frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {\int \frac {\left (-126 d^6 e^5+105 d^5 e^6 x\right ) \left (d^2-e^2 x^2\right )^{3/2}}{x} \, dx}{42 d^2 e^4} \\ & = \frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}+\frac {\int \frac {\left (504 d^8 e^7-315 d^7 e^8 x\right ) \sqrt {d^2-e^2 x^2}}{x} \, dx}{168 d^2 e^6} \\ & = \frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {\int \frac {-1008 d^{10} e^9+315 d^9 e^{10} x}{x \sqrt {d^2-e^2 x^2}} \, dx}{336 d^2 e^8} \\ & = \frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}+\left (3 d^8 e\right ) \int \frac {1}{x \sqrt {d^2-e^2 x^2}} \, dx-\frac {1}{16} \left (15 d^7 e^2\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = \frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}+\frac {1}{2} \left (3 d^8 e\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {d^2-e^2 x}} \, dx,x,x^2\right )-\frac {1}{16} \left (15 d^7 e^2\right ) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right ) \\ & = \frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {15}{16} d^7 e \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )-\frac {\left (3 d^8\right ) \text {Subst}\left (\int \frac {1}{\frac {d^2}{e^2}-\frac {x^2}{e^2}} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{e} \\ & = \frac {3}{16} d^5 e (16 d-5 e x) \sqrt {d^2-e^2 x^2}+\frac {1}{8} d^3 e (8 d-5 e x) \left (d^2-e^2 x^2\right )^{3/2}+\frac {1}{10} d e (6 d-5 e x) \left (d^2-e^2 x^2\right )^{5/2}-\frac {1}{7} e \left (d^2-e^2 x^2\right )^{7/2}-\frac {d \left (d^2-e^2 x^2\right )^{7/2}}{x}-\frac {15}{16} d^7 e \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )-3 d^7 e \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \\ \end{align*}
Time = 0.59 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.00 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (-560 d^7+2496 d^6 e x+525 d^5 e^2 x^2-992 d^4 e^3 x^3-770 d^3 e^4 x^4+96 d^2 e^5 x^5+280 d e^6 x^6+80 e^7 x^7\right )}{560 x}+\frac {15}{8} d^7 e \arctan \left (\frac {e x}{\sqrt {d^2}-\sqrt {d^2-e^2 x^2}}\right )-3 d^6 \sqrt {d^2} e \log (x)+3 d^6 \sqrt {d^2} e \log \left (\sqrt {d^2}-\sqrt {d^2-e^2 x^2}\right ) \]
[In]
[Out]
Time = 0.43 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.37
method | result | size |
risch | \(-\frac {d^{7} \sqrt {-e^{2} x^{2}+d^{2}}}{x}+\frac {e^{7} x^{6} \sqrt {-e^{2} x^{2}+d^{2}}}{7}+\frac {6 e^{5} d^{2} x^{4} \sqrt {-e^{2} x^{2}+d^{2}}}{35}-\frac {62 e^{3} d^{4} x^{2} \sqrt {-e^{2} x^{2}+d^{2}}}{35}+\frac {156 e \,d^{6} \sqrt {-e^{2} x^{2}+d^{2}}}{35}-\frac {3 e \,d^{8} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}+\frac {d \,e^{6} x^{5} \sqrt {-e^{2} x^{2}+d^{2}}}{2}-\frac {11 d^{3} e^{4} x^{3} \sqrt {-e^{2} x^{2}+d^{2}}}{8}+\frac {15 d^{5} e^{2} x \sqrt {-e^{2} x^{2}+d^{2}}}{16}-\frac {15 d^{7} e^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{16 \sqrt {e^{2}}}\) | \(265\) |
default | \(-\frac {e \left (-e^{2} x^{2}+d^{2}\right )^{\frac {7}{2}}}{7}+d^{3} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {7}{2}}}{d^{2} x}-\frac {6 e^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{6}+\frac {5 d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4}+\frac {3 d^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )}{d^{2}}\right )+3 d \,e^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{6}+\frac {5 d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4}+\frac {3 d^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )+3 d^{2} e \left (\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{5}+d^{2} \left (\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{3}+d^{2} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )\right )\right )\) | \(357\) |
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 167, normalized size of antiderivative = 0.87 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=\frac {1050 \, d^{7} e x \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + 1680 \, d^{7} e x \log \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{x}\right ) + 2496 \, d^{7} e x + {\left (80 \, e^{7} x^{7} + 280 \, d e^{6} x^{6} + 96 \, d^{2} e^{5} x^{5} - 770 \, d^{3} e^{4} x^{4} - 992 \, d^{4} e^{3} x^{3} + 525 \, d^{5} e^{2} x^{2} + 2496 \, d^{6} e x - 560 \, d^{7}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{560 \, x} \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 3.25 (sec) , antiderivative size = 887, normalized size of antiderivative = 4.60 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=\text {Too large to display} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 231, normalized size of antiderivative = 1.20 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=-\frac {15 \, d^{7} e^{2} \arcsin \left (\frac {e^{2} x}{d \sqrt {e^{2}}}\right )}{16 \, \sqrt {e^{2}}} - 3 \, d^{7} e \log \left (\frac {2 \, d^{2}}{{\left | x \right |}} + \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d}{{\left | x \right |}}\right ) - \frac {15}{16} \, \sqrt {-e^{2} x^{2} + d^{2}} d^{5} e^{2} x + 3 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{6} e - \frac {5}{8} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{3} e^{2} x + {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{4} e + \frac {1}{2} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d e^{2} x + \frac {3}{5} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d^{2} e - \frac {1}{7} \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}} e - \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d^{3}}{x} \]
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.16 \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=-\frac {15 \, d^{7} e^{2} \arcsin \left (\frac {e x}{d}\right ) \mathrm {sgn}\left (d\right ) \mathrm {sgn}\left (e\right )}{16 \, {\left | e \right |}} + \frac {d^{7} e^{4} x}{2 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} {\left | e \right |}} - \frac {3 \, d^{7} e^{2} \log \left (\frac {{\left | -2 \, d e - 2 \, \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |} \right |}}{2 \, e^{2} {\left | x \right |}}\right )}{{\left | e \right |}} - \frac {{\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} d^{7}}{2 \, x {\left | e \right |}} + \frac {1}{560} \, {\left (2496 \, d^{6} e + {\left (525 \, d^{5} e^{2} - 2 \, {\left (496 \, d^{4} e^{3} + {\left (385 \, d^{3} e^{4} - 4 \, {\left (12 \, d^{2} e^{5} + 5 \, {\left (2 \, e^{7} x + 7 \, d e^{6}\right )} x\right )} x\right )} x\right )} x\right )} x\right )} \sqrt {-e^{2} x^{2} + d^{2}} \]
[In]
[Out]
Timed out. \[ \int \frac {(d+e x)^3 \left (d^2-e^2 x^2\right )^{5/2}}{x^2} \, dx=\int \frac {{\left (d^2-e^2\,x^2\right )}^{5/2}\,{\left (d+e\,x\right )}^3}{x^2} \,d x \]
[In]
[Out]